Anyone good at math??

If the fraction is x^(a/b), then the thing becomes the b root of (x^a).

Make sense?

So if it's x^(1/2), then its the 2nd root of (x^1), or the square root of x.
(So the answer to your questions would be the 5th root of 2 and the 5th root of 125)

 

odds of google answering ur question correctly: highly/probable

odds of stoner answering ur question correctly: .......

dude above me wins lottery i guess..

 

Haha, I took calculus in high school, lots of exponents involved.

 

If it's fifth root of 5 divided by fifth root of 125, you can rationalize the denominator by multiplying the entire equation. I'll upload a picture, hold up.

 

Glad im only doing negative exponents haha

 

I don't know man there're some very smart people here

 

Alright, so you basically multiply the fraction by the 5th root of (125^4). This way, you get 125 on the denominator since you're basically multiplying (125^0.2) and (125^0.8), so you just add the exponents and get 125^1 = 125.

Edit: I derped and the photo's upside down. Hopefully you understand it though.

 

Damn. I hate math

 

I believe this blade is right.

 

oh i know man, im not giving stoners a negative connotation im just saying i would trust a calculator doing my math more than a random person

 

No problem, dude.

 

Converting to logs would be your best bet

 

You really only need to convert to logarithms when you're evaluating unknown exponents though (ex: 6^x = 28). The exponents are given here.

 

Wolframalpha.com

You will never need math help again.