i have read most of that and continued on with some research. i just started making cs today and going to be testing it out very soon.
i still have a few questions though.
1 - if i have the pheno of c99 that i want to breed, but that strain has 3 main phenos, what are the chances of getting a different phenotype if i breed the one i have, with itself? should i still cube it so it always stays the same or only cube it if i find a different phenotype?
im having trouble selecting a strain to breed it with to add mass but keep most of the c99 genetics. its parents are jack herer which is(sk#1 x NL#5 x original haze) and shiva skunk which is (sk#1 x NL#5)
2 - should i find a high yielding skunk strain that has sk#1 in its genetics? or just find any strain that has a high yield? id like to try and keep most of the genetics the same but it needs more weight.
any ideas or suggestions for strains???
Hey man, Ok so theoretically. If the plant has 3 different pheno's and your crossing it with itself. You could end up with all 3 phenos randomly in the mix. Now its what you do with those beans from the first cross. Like this:
P1 x P1 = F1 (100%+0%/2 = 50%)
With F1 you have a mix of all the phenos that the strain could possibly produce. But what you want to do is keep on popping your F1 beans, untill you find one that has multiple phenos that you like or are looking for. Then cross it back with one of the parents that has the more desireable traits.
P1 x F1 = B1 (100%+50%/2=75%)
Then you would end up with roughly 75% by mathwise atleast to be like the P1 that you chose to back cross with. So with each back cross back you are taking the newest B1,B2,B3 and crossing it back with P1 or P2 and making the selected pheno's that you found more pronounced each cross till you have similarity among all the beans.
P1 x B1 = B2 (100%+75%/2=87.5%)
Then take the B2 and back cross them one final time to the P1.
P1 x B2 = B3 (100%+87.5/2=93.75%)
So in theory with this cross you should have about 93.75% of your beans that are B3 will be the same, And with that you should have only a low amount of 7% atleast math wise that can vary from the rest of the bunch. Now it doesnt work pefectly like this but that is the simple way to think about it.
Once your strain is stable it becomes a Ibl (Inbred Line) and you start all over with that IBL and introduce a new partner P2 and introduce new traits that aventually after back crossing and cubing to single out those pheno's you have your newest IBL with all said combinations that your hopeing for uniformly in seed stock.
Atleast thats where I am getting, IDK Im tired at the moment so my head isnt completly straight. I just hope that when I read this tomorrow it comes out how it did in my head.
Lols Happy smokin and growin.
And as far as finding another strain that is heavy yeilding. I would try and find one that is totally different, as in not related to the original cross at all in hopes that you could get hybrid vigor in the newest set of beans by introducing to completley different strains together!
But if you really want to single out a certain trait like hard core, approach like this..
P1 x P1 = F1
F1 x F1 = F2
Go as far as F3 or F4 then your selection will be huge. Pretty much you will have endless pheno's So out of those then take the ones that are the best in your eyes, or show the traits that you desire most and then start cubing them.
F4 x P1 =B1 and so on and so forth. The combinations are endless really. It all depends on time and patients. Really! Good luck
Like I said I hope this sounds right and I will be back to see if you have further questions or if your more confuesed then when you started lols.
Happy smokin and growin.
Edited by WaGreenGuru, 26 June 2012 - 11:32 AM.