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Plain Ol' Stoner
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Ventilation vs. CO2
Okay, I'm preparing long in advance for a grow room setup.
Based on what I've read (in the Overgrow FAQ on ventilation) on the ventilation front, ideally the output fan should replace the volume of the grow room 2-3 times per minute. As for CO2, supposedly the goal concentration of the air should be 2000ppm CO2, or .2%. This I got from one of the growing books I purchased, Marijuana Grower’s Handbook by Ed Rosenthal. I should note, though, that in his book, he doesn’t mention anything about exchanging the air. It seems assumed that the air in the grow room will be stagnant. So here's some mathematical formulas I came up with while figuring out how to maintain a 2000ppm CO2 level while simultaneously replacing the air in the room 2-3 times per minute. <o =""></o>To supply the CO2 to the room, I plan on using a CO2 tank with a flow meter/regulator. For the purposes of these equations, I'll use these variables: v - Volume of the grow room (cubic feet) C - CFM of the output fan(s) x - Number of times that the air in the room is exchanged completely each minute F1 - Total hourly airflow out of the room (cubic feet) F2 - Hourly CO2 flow out of the room (and therefore the necessary flow out of the CO2 tank to replace the gas that left the room) ![]() So, although I’m yet to choose a grow room, I’ll say that the maximum size available will be 10×10×10. <o =""></o>http://www.purennatural.com/prod_desc.php?prod_id=597 That’s the output fan I’ve chosen (for the ozone odor control, largely). Assuming I need to change the air in the room 2 times/minute, I would buy 5. I know, expensive, but this is an investment for me and the first harvest will hopefully be worth it. <o =""></o>So now I have enough given information to solve for F2, the amount of CO2 I need flowing out of my tank to give the plants what they want. v=1000 C=2000 ![]() Someone let me know if my math is flawed somewhere, but according to those calculations, a 10 ft. × 10 ft. × ft. grow room with 2000 CFM total would need 240 cubic feet of CO2 per hour to maintain the .2% recommended.<o =""></o> Although I haven’t looked at any CO2 tanks/regulators, Rosenthal’s book says they usually can release up to 50 cubic feet per hour. I’d need 5 tanks all pumping out CO2 at full blast simultaneously to get the amount of CO2 I’m after. Did I read something wrong? Was I misinformed? It seems to me that replacing the air in the grow room 2× per minute is a lot of airflow, and to try to constantly replace all that CO2 is going to be difficult. Basically I’m just looking for someone to either help me out with ventilation and CO2, or to tell me I fucked up with my math. Edit: My bad, I meant to put this in Grow Room Design/Setup. Sorry!<o =""></o>
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The function of government is to protect me from others. It's up to me, thank you, to protect me from me. - Arthur Hoppe |
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One Step Closer
Join Date: Nov 2004
Location: Canada
Posts: 312
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I found a Co2 generator thats double that 36 CFH.
http://www6.mailordercentral.com/igc...number=CO-1001 Might be of interest? You said that you'll need 5 tanks running full blast. Hmm? What size tanks? Are we talking 50LB tanks? Or 100LBs? Or 20LBS? I'd say the size of the tank will determine the amount of CO2 output as well as the valving (I think)... Any ways, just trying to help Good luck
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Potheads gathered in their masses. Just like schoolkids in their classes. Sober minds that need instructions, on power of leafs seductions. In the fields the crops burning, as the war machine keeps turning. Pot and love to mankind, resonates in smoky minds. |
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Plain Ol' Stoner
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Quote:
Anyway, as far as I know the size of the CO2 tank doesn't matter, it's all in the valving. While I haven't actually gone tank-shopping, from what I read most regulators allow 10-50 cubic feet/hour.
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The function of government is to protect me from others. It's up to me, thank you, to protect me from me. - Arthur Hoppe Last edited by Fëanor; 12-08-2005 at 06:40 AM. |
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